(1)由图知,n=2绳子自由端移动的距离:s=2h=2×0.2m=0.4m,绳子自由端移动的速度:v= s t = 0.4m 2s =0.2m/s;故A错;(2)∵绳子的重力和摩擦力不计,∴F拉= G+G动 n = 8N+2N 2 =5N,故C错、D正确;(3)滑轮组的机械效率:η= W有 W总 = Gh Fs = G nF = 8N 2×5N =80%;故B错.故选D.