x>0, y > 0, 得 x+1 > 0, y+2 > 02/(x+1) + 4/(y+2) = 1得 2(y+2) + 4(x+1) = (x+1)(y+2) = xy+2x+y+2即 xy-(2x+y)-6 = 0又 2x+y ≥ 2√(2xy) = 2√2 √(xy)则 xy - 2√2 √(xy) - 6 ≥ 0即 [√(xy)-3√2][√(xy)+√2] ≥ 0得√(xy) ≥ 3√2, 即 xy ≥ 18, xy 最小值是 18。