异分母分式的加减计算。 1÷(x+2)-2÷(x-2) x-2-x^2÷(x-2) 计算(4⼀a^2-4)+(1⼀2-a)

1÷(x+2)-2÷(x-2) x-2-x^2÷(x-2) (4⼀a^2-4)+(1⼀2-a)
2025-06-27 21:44:17
推荐回答(2个)
回答1:

1÷(x+2)-2÷(x-2)
=[(x-2)-2(x+2)]÷[(x+2)(x-2)
=(-x-6)/(x²-4)

x-2-x^2÷(x-2)
=[(x-2)²-x²]÷(x-2)
=(-4x+4)/(x-2)

(4/a^2-4)+(1/2-a)
=[4-(a+2)]/(a²-4)
=(2-a)/(a+2)(a-2)
=-1/(a+2)

回答2:

1÷(x+2)-2÷(x-2)
=x-2-2(x+2)/(x+2)(x-2)
=-x-6/(x+2)(x-2)
x-2-x^2÷(x-2)
=(x-2)²-x²/x-2
=4(-x+1)/x-2

计算(4/a^2-4)+(1/2-a)
=1/(a+2)(a-2)- a+2/(a+2)(a-2)
=-a-1/(a+2)(a-2)