z变换E(z)=z⼀(z-e^-aT)(z-e^-bT),其反变换是多少????

2025-06-24 12:53:39
推荐回答(1个)
回答1:

x(kT)=∑res[1/(1-z^2)*z^(k-1)]=1/[(1-z)(1+z)]
=∑res{1/[(1-z)(1+z)]*z^(k-1)}
=1/[(1-z)(1+z)]*z^(k-1)*(z-1)|(z=1)+1/[(1-z)(1+z)]*z^(k-1)*(z+1)|(z=-1)
=(-1)^(k-1)/2-1/2 k=0,1,2……