cos61°?cos127°+cos29°?cos37°=-sin29°?sin37°+cos29°?cos37°=cos(37°+29°)=cos66°,即a=cos66°=sin24°,
=2tan?13?
1+tan?213?
=2sin?13?cos?13?=sin?26?2
sin?13?
cos?13?
sin?13?+cos?13?
cos?213?
=
1?cos50° 2
=
1?1+2sin225° 2
=sin25°.
sin225°
∵sin24°<sin25°<sin26°,
∴a<c<b,
故答案为:a<c<b.