1/4<1/2=1-1/21/9<1/6=1/2-1/31/16<1/12=1/3-1/4……所有的和就<(1-1/2)+(1/2-1/3)+(1/3-1/4)+…+(1/(n-1)-1/n)=1-1/n<1。
1/n^2<1/(n+1/2)(n-1/2)=1/(n-1/2)-1/(n+1/2)所以原式<1/1.5-1/2.5+1/2.5-1/3.5......<1/1.5<1