请采纳
y=arctan√(x+1)y'=[arctan√(x+1)]'=[1/(1+x+1)]·[√(x+1)]'=[1/(x+2)]·½(x+1)'/√(x+1)=[1/(x+2)]·½/√(x+1)=1/[2(x+2)√(x+1)]dy=dx/[2(x+2)√(x+1)]
百度是最好的老师
