lim x->2 sin(x^2-4)⼀x-2=过程啊

2025-06-29 03:14:51
推荐回答(1个)
回答1:

解法一:等价无穷小
lim sin(x²-4)/(x-2)
x→2
=lim (x²-4)/(x-2)
x→2
=lim (x+2)(x-2)/(x-2)
x→2
=lim (x+2)
x→2
=2+2
=4
解法二:洛必达法则
lim sin(x²-4)/(x-2)
x→2
=lim 2x·cos(x²-4)/1
x→2
=2·2·cos(2²-4)
=4·cos0
=4·1
=4