由y+1/z=1,得1/z=1-yz=1/(1-y)=(1-y+y)/(1-y)=1+y/(1-y)将其代入z+1/x=1,得1+y/(1-y)+1/x=1则:y/(y-1)=1/x则:x=(y-1)/y=1-1/y,即:x+1/y=1