(1)等差数列{an}中,∵a4-a2=4,∴2a=4,∴d=2∵S5=30,∴5a1+10d=30,∴a1=2∴an=2n;等比数列{bn}中,bn+1=3bn,b1=3,∴bn=3?3n?1=3n;(2)Tn=2?31+4?32+…+2n?3n∴3Tn=2?32+4?33+…+(2n?2)?3n+2n?3n+1两式相减可得?2Tn=2?31+2?32+4?32+…+2?3n?2n?3n+1=-3-(2n-1)?3n+1∴Tn= 2n?1 2 ?3n+1+ 3 2 .