∫∫√a^2-x^2-y^2dσ,D={(x,y)x^2+y^2≤a^2}

∫∫√a^2-x^2-y^2dσ,D={(x,y)x^2+y^2≤a^2}求过程谢谢
2025-06-24 19:27:41
推荐回答(1个)
回答1:

这个题是吧
设x=r cost,y=r sint
则0原式=∫[0,2π]dt ∫[0,a] √(a²-r²) rdr
=2π ∫[0,a] √(a²-r²) rdr
=-π ∫[0,a] √(a²-r²) d(a²-r²)
=-π 2/3 (a²-r²)^(3/2) |[0,a]
=-2π/3 (0-a^3)
=2πa^3 /3