设方程y=xe^y 2确定y是x的函数,求dy

求dy/dx(x=0)
2025-06-27 20:43:14
推荐回答(1个)
回答1:

y'=e^y+xe^y ·y'
(1-xe^y)y'=e^y
y'=e^y/(1-xe^y)
dy=e^y/(1-xe^y)dx
x=0,y=0
所以

dy/dx(x=0)
=1/1
=1