已知数列{a n }的前n项和 S n =3?( 3 2 ) n-1 -1(n∈ N * ) ,数列{b n }满足 b

2025-06-24 09:30:02
推荐回答(1个)
回答1:

(1)当n=1时,a 1 =S 1 =3×1-1=2;
当n≥2时,a n =S n -S n-1 = (
3
2
) n-1

a n =
2,n=1
(
3
2
)
n-1
,n≥2

∵n=1时,a 1 =S 1 =3×1-1=2不满足 a n =(
3
2
)
n-1

∴{a n }不是等比数列;
(2)∵ b n =
a n+1
log
3
2
a n+1
=
(
3
2
) n
n

1
b n
= n?(
2
3
) n

∴数列 {
1
b n
}
的前n项和前T n = 1?
2
3
+2?(
2
3
) 2 +…+n? (
2
3
)
n

2
3
T n =1?(
2
3
) 2 +2? (
2
3
)
3
+…+n? (
2
3
)
n+1

两式相减可得
1
3
T n =
2
3
+ (
2
3
)
2
+ (
2
3
)
3
+…+(
2
3
) n -n? (
2
3
)
n+1
= 2-2?(
2
3
) n -n?(
2
3
) n+1

∴T n = 6-2(n+3)(
2
3
) n

(3)由(2)有b n+1 -b n =
(
3
2
)
n+1
n+1
-
(
3
2
)
n
n
= (
3
2
) n ?
n-2
2n(n+1)

∴n≤2时,有b n+1 -b n ≤0;n>2时,b n+1 -b n >0
∴b n 的最小值为b 2 =b 3 =
9
8

∴-
8
3
b n >2t- t 2
等价于-
8
3
×
9
8
>2t- t 2

∴t 2 -2t-3>0
∴t>3或t<-1
∴t的最小正整数值是4.