1,如图,已知∠AOB=90°,∠BOC=60°,∠AOC=3∠AOM,∠BOC=3∠BON,求∠

2025-06-23 21:52:27
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回答1:

(1)∠MON=∠MOC-∠NOC=(∠AOC-∠AOM)-(∠BOC-∠BON)
∵∠AOC=∠AOB+∠BOC=150° ∠BOC=60°
∴∠AOM=50° ∠BON=20°
∴∠MON=60°
(2)∠MON=∠MOC-∠NOC=(∠AOC-∠AOM)-(∠BOC-∠BON)
=(2/3)∠AOC-40°
=(2/3)(α+60°)-40°
=(2/3)α
(3)∠MON=∠MOC-∠NOC=(∠AOC-∠AOM)-(∠BOC-∠BON)
=(2/3)(∠AOC-∠BOC)