x²+2x+y²–6y+10＝0(x^2+2x+1)+(y^2-6y+9)=0(x+1)^2+(y-3)^2=0得{x+1=0 y-3=0即 x=-1, y=3
(x^2+2x+1)+(y^2-6y+9)=0(x+1)^2+(y-3)^2=0x+1=0y-3=0x=-1y=3
（X+1）∧2+（y-3）∧2=0
