若x1 ,x2 是方程2x(平方)-4x+1=0的两个根,则(x2分之x1)+(x1分之x2)的值为?

2025-06-28 02:53:48
推荐回答(1个)
回答1:

答案:B2x2-4x+1=0根据根与系数之间的关系得,x1+x2=2,x1x2=1/2x1/x2+x2/x1=(x12+x22)/x1x2 =[(x1+x2)2-2x1x2]/x1x2 =6 x4-16=(x2)2-42 =(x2+4)(x2-4) =(x2+4)(x+2)(x-2)