f(x)=lncosx,则f(x)的两次求导是多少??

2025-06-27 19:50:35
推荐回答(3个)
回答1:

f(x)导数=-sinx/cosx
f(x)二次导数=-1/cos^2x

回答2:

f'(x)=(1/cosx)*(-sinx)=-tanx
f''(x)=(-tanx)'=-(secx)^2

回答3:

-sinx - (sinx)'cosx + sinx(cosx)' -1
(______)' =(lncosx)'' = _________________________ = _________ =-sec�0�5x
cosx cos�0�5 x cos�0�5x