1)
由(x+y)²=4,得,
x²+2xy+y²=4,①
由(x-y)²=3,得,
x²-2xy+y²=3,②
①+②,得,
2(x²+y²)=7
所以x²+y²=7/2
2)①-②,得,
4xy=1,
解得xy=1/4
(x+y)²=x²+y²+2xy=4
(x-y)²=x²+y²-2xy=3
上式分别相加求得(1)=3.5
上式分别相减求得(2)=0.25
(x+y)²=4 (x-y)²=3
x²+y²=1/2(x+y)²+1/2(x-y)²=7/2
xy=1/4((x+y)²-(x-y)²)=1/4
xy的值是四分之一
x²+y²的值是3.5