则此波的波长为____0.6m_____,波速为____0.125m/s_____,周期为___4.8s____.因为：第一个波峰的半径扩展为6m时，第十个波峰恰在圆心形成，由图第一个波峰到第十个波峰刚好10个波长所以：波长=6m/10=0.6m波速=s/t=5m/40s=0.125m/s周期=波长/波速=0.6m/0.125m/s=4.8s
