∵Y满足Y=根号X-1+根号1-X+1∴x-1≥0 1-x≥0∴x=1 y=1∴根号X+3次根号Y的值=√1+³√1=1+1=2
Y=根号X-1+根号1-X+1∴﹛x-1≥0 1-x≥0x=1此时y=1∴根号X+3次根号Y=1+1=2
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