∫[0->π⼀2](sinx)^ndx=?

2025-06-27 22:24:49
推荐回答(2个)
回答1:

若n是奇数,
∫(0,π/2) sinⁿx dx = (n - 1)!!/n!!
若n是偶数,
∫(0,π/2) sinⁿx dx = (n - 1)!!/n!! * π/2

n!!是双阶乘,n!! = (n - 2)!! * n
= (n - 4)!! * (n - 2) * n
= (n - 6)!! * (n - 4) * (n - 2) * n
= ...

回答2:

不好意思!我没有学过