，
2<|2x–5|≤7→2＜2x-5＜7 (2x-5≥0)→7＜2x＜12→7/2＜x＜6→2＜-(2x-5)＜7 (2x-5＜0)→-2＞2x-5＞-7→3＞2x＞-2→3/2＞x＞-1 即：-1＜x＜3/2∴不等式的解为：7/2＜x＜6；-1＜x＜3/2
