(1)原式=x^2(x-y)-4x(x-y)
=(x-y)(x^2-4x)
=x(x-y)(x-4)
(2)可以看出三个部分组成一个完全平方式,所以,
原式=(a^2+2ab+b^2)^2
=[(a+b)^2]^2
=(a+b)^4
(3)原式=(x+y)[(x+y)^2-(x-y)^2]
=(x+y)(x+y+x-y)(x+y-x+y) {此步利用了平方差公式}
=4xy(x+y)