∫dx/(a^2sin^2x+b^2cos^2x)=∫dx/a^2*cos^2x*(tan^2x+b^2/a^2)=1/a^2∫sec^2xdx/(tan^2x+b^2/a^2)=1/a^2∫d(tanx)/(tan^2x+(b/a)^2)=1/a^2*a/b*arctan(ax/b)+C=(1/ab)*arctan(ax/b)+C希望对你有所帮助 还望采纳~~
