线性代数矩阵的运算

2025-06-26 11:47:16
推荐回答(1个)
回答1:

A^(-1) 是范德蒙矩阵,|A^(-1)| = (2-1)(3-1)(3-2) = 2, 则 |A| = 1/2.
A^(-1) = A*/|A| , 则 A* = |A|A^(-1) =
[1/2 1/2 1/2]
[1/2 1 3/2]
[1/2 2 9/2]