1》 public static boolean isOdd(int n) {
return ((n%2)!=0) ? true : false;
}
2》写的不够好,欢迎指正
String a = "AABBBCDwEFdGHIiiiiiJK";
List
Map
for(int i=0;i
if(i>0){
String old = list.get(list.size()-1);
if(old.equals(str)){
if(!maps.containsKey(old)){
maps.put(old, 2);
}else{
Integer num = (Integer) maps.get(old);
maps.put(old, num+1);
}
}
}
list.add(str);
}
for(Map.Entry en:maps.entrySet()){
System.out.println(en.getKey() + "==" + en.getValue());
}
3》php:
echo strrev("Hello World!");
?>
4》:
SELECT AVG(sal) AS v FROM emp WHERE deptno=10 AND job = '工程师'
UPDATE emp SET job = '经理' AND sal=sal+1000 WHERE NAME='JONES'
SELECT job FROM emp WHERE deptno = 10 GROUP BY job
DELETE FROM emp WHERE id = 100512
5》:
java计划任务吧。
public static bolean isOdd(int n) { return n%2==1} 理由,查看是否是基数偶数