x^2-x-1=0
题目应是
先化简,再求值;(x-1/x-x-2/x+1)除以2x²-x/x²+2x+1,其中x满足x²-x-1=0
x²-x-1=0
x^2=x+1
(x-1/x -x-2/x+1)÷2x²-x/x²+2x+1
=((x-1)(x+1)-x(x-2))/x(x+1)÷(x(2x-1)/(x+1)^2)
=((x^2-1-x^2+2x)/x(x+1))÷(x(2x-1)/(x+1)^2)
=(2x-1)/x(x+1) * (x+1)^2/x(2x-1)
=(x+1)/x^2
=x^2/x^2
=1
题目没出完吧，前面括号下，看不明白
- -兄弟~题目写好啊~~~~~~~~
内容全部来源于网络收集，如有侵权，请联系网站删除：QQ：24596024