根据下列条件求代数式-b+√b눀-4ac ⼀2a 的值 (1)a=1 b=8 c=-4 (2)a=3,b=-6,c=2

2025-06-28 21:40:01
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回答1:

(1)
(-8+√(64-4×1×(-4)))/2×1
=(-8+√80)/2
=(-8+4√5)/2
=-4+2√5
(2)(6+√(36-4×2×3))/2×3
=(6+√12)/6
=(6+2√3)/6
=(3+√3)/3