∫∫1/xy×f(x,y)dxdy=(3/2)∫(1,十∞)(1/x^4)dx∫(1/x,x)(1/y³)dy= (3/2)∫(1,十∞)(1/x^4)dx[(-1/2)1/y²](1/x,x)= (-3/4)∫(1,十∞)(1/x^4)[1/x²-x²]dx= (-3/4)∫(1,十∞)[1/x^6-1/x²]dx= (-3/4)[(-1/5)1/x^5-(-1)1/x] (1,十∞)= (-3/4)[(-1/5)(0-1)十(0-1)] = (-3/4)(-4/5)=3/5