∵a+b=5,ab=3,∴(a+b)2=25,∴a2+b2+2ab=25,∴a2+b2+2×3=25,∴a2+b2=19,∵a3b-2a2b2+ab3=ab(a2-2ab+b2)=ab(a-b)2=ab[(a+b)2-4ab]∴原式=ab[(a+b)2-4ab]=3×(52-4×3)=3×13=39.故答案为:19,39.