化为二重积分来讨论：∫[0->1](x^(p-1)-x^(q-1))dx/lnx=∫[0->1]dx∫[q->p] x^(y-1) dy=∫[q->p]dy∫[0->1] x^(y-1) dx=∫[q->p] (1/y) dy=ln|p|-ln|q|故当p≠0或q≠0,或者p,q同时为0时,积分收敛
