怎样求正切函数的导数

2025-06-26 23:14:23
推荐回答(2个)
回答1:

(tan x )'=(sin x /cos x)'
=[(sin x)'cos x-sin x(cos x)']/cosx*cos x
=[cos x*cos x-(-sin x*sin x)]/cos x*cos x
=1/cos x*cos x
=1/cos^2x.

回答2:

cos^2x-sin^2x=cos2x=2cos^2x-1=1-2sin^2x≠1