计算:(2+1)(2^2+1)(2^4+1)……(2^32+1)+1=??

2025-06-29 05:49:11
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回答1:

原式=(2-1)(2+1)(2^2+1)(2^4+1)……(2^32+1)+1
=(2^2-1)(2^2+1)(2^4+1)……(2^32+1)+1
=2^64-1+1
=2^64