由原题目可知，(x^2+ax+b)*x-(x^2+ax+b)=x^3-b*x^2+11x-bx^3+a*x^2+bx-x^2-a*x-b=x^3-b*x^2+11*x-bx^3+(a-1）x^2+(b-a)x-b=x^3-b*x^2+11*x-b所以，a-1=-b,b-a=11所以，a=-5. b=6
