已知tana=3,求sin平方a-2sinacosa 3cos平方a

2025-06-28 22:20:03
推荐回答(1个)
回答1:

sin^2a-2sinacosa+3cos^2a
=(sin^2a-2sinacosa+3cos^2a)/(sin^2a+cos^2a)
=(tan^2a-2tana+3)/(tan^2a+1)
=(9-6+3)/(9+1)
=6/10
=3/5