证明曲线积分与路径无关题, ∫(1,2)到(3,4)(6xy^2-y^3)dx+(6x^2y-3xy^2)dy.

2025-06-29 01:05:45
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回答1:

P(x,y)=6xy^2-y^3,Q(x,y)=6x^2y-3xy^2
偏P/偏y=12xy-3y^2;偏Q/偏y=12xy-3y^2==>偏P/偏y=偏Q/偏y==>该曲线积分与路径无关.