1）F = (A'BD+AC'+B'CD')'+(B'D'+AC)'
= (A'BD)'(AC')'(B'CD')' + (B'D')'(AC)'
= (A+B'+D')(A'+C)(B+C'+D) + (B+D)(A'+C')
= (AC+B'A+B'C+D'A'+D'C)(B+C'+D) + (A'B+BC'+A'D+C'D)
= (ABC+A'BD'+BCD' + AB'C'+A'C'D' + ACD+AB'D+B'CD)+(A'B+BC'+A'D+C'D)
= B + C'+ D 为删繁就简，中间多步省略!
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