难道我画的图和你的不同？我证出这个∵BD平分∠ABC∴∠ABD = ∠DBC∵DE //BC∴∠EDB = ∠DBC∴∠ABD = ∠EDB∴EB = ED∵CD是∠ACG的平分线∴∠ACD = ∠DCG∵ED//BC∴∠FDC = ∠DCG∴∠ACD = ∠FDC∴FC = FD∵EF = ED-FD ∴EF = EB - FC
