(2x²+2x+13)/[(x-2)(x²+1)²]=A/(x-2)+(Bx+C)/ (x²+1)²+(Dx+E)/ (x²+1)A/(x-2)+[Bx+C+(Dx+E)(x²+1)]/(x²+1)² (x-3)/[(x-1)²(x+1)]=(Ax+B)/(x-1)²+C/(x+1)=(Ax+A-A+B)/(x-1)²+C/(x+1)=A/(x-1)+(-A+B)/(x-1)²+C/(x+1)
