计算 (lg根号27+lg8-lg根号1000)⼀lg1.2

2025-06-26 06:21:43
推荐回答(2个)
回答1:

lg根号27+lg8-lg根号1000=lg[根号(27x8^2/1000)]=lg1.2^3/2(注:1.728=1.2x1.2x1.2)

原式=3/2

回答2:

原式=(3/2lg3+3lg2-3/2)/(lg12-1)
=3/2(lg3+2lg2-1)/(lg12-1)
=3/2(lg12-1)/(lg12-1)=3/2