(1)先化简,再求值:(a+1)2-(3a2+a)÷a,其中a=-3.(2)已知x+y=3,xy=-2.求(x-1)(y-1)的值

2025-06-28 02:17:57
推荐回答(1个)
回答1:

(1)(a+1)2-(3a2+a)÷a
=a2+2a+1-3a-1
=a2-a,
当a=-3时,原式=(-3)2-(-3)=12.

(2)当x+y=3,xy=-2时,
(x-1)(y-1)
=xy-x-y+1
=-2-3+1
=-4.