原式=(lg√3�0�6+lg√4�0�6-lg√10�0�6)/(lg12-1)=[(3/2)lg3+(3/2)lg4-(3/2)lg10]/(lg12-1)=(3/2)(lg3+lg4-lg10)/(lg12-1)=(3/2)(lg(3×4)-1)/(lg12-1)=(3/2)(lg12-1)/(lg12-1)=3/2
