定积分∫√x^2-2⼀xdx

2025-06-29 01:16:35
推荐回答(2个)
回答1:

求采纳

回答2:

∫√x^ √ 2-2/xdx
= √ [-2 + x^2] + √ [2] ArcTan[ √ [2]/ √ [-2 + x^2]]+c