a-bx^2=(√a-√bx)(√a+√bx)1/(a-bx^2) = [1/(2√a)] [1/(√a-√bx)+ 1/(√a+√bx) ]∫ dx/(a-bx^2)=[1/(2√a)] ∫ [1/(√a-√bx)+ 1/(√a+√bx) ] dx=[1/(2√(ab) )] ln|(√a+√bx)/(√a-√bx) | + C
