解，f(ⅹ-2)+f(4-3x)
=loga[(1-(x-2))/(1+(x-2))]+loga[(1-(4-3x))/[(1+(4-3x)
=loga[(3-x)/(x-1)]+loga[(3x-3)/(5-3x)]
=Ioga[(3-x)(3x-3)/(x-1)(5-3x)]
≥0
则(3-x)(3x-3)/(x-1)(5-3x)≥1
而(3-x)/(x-1)>0，且(3x-3)/(5-3x)>0
则x∈(1，3)，X∈(1，5/3)
9x-9-3x^2+3x≥5x-3x^2-5+3x
4x≥4
则x∈(1，5/3)
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